Base | Representation |
---|---|
bin | 10110010011001110111… |
… | …011101101010111101111 |
3 | 12102111121011200222221111 |
4 | 112103032323231113233 |
5 | 200102004402204312 |
6 | 3132002303212451 |
7 | 215501200026625 |
oct | 26231673552757 |
9 | 5374534628844 |
10 | 1532480116207 |
11 | 540a1508a437 |
12 | 2090085a7127 |
13 | b1687568591 |
14 | 5425b22b515 |
15 | 29ce3ac28a7 |
hex | 164ceeed5ef |
1532480116207 has 4 divisors (see below), whose sum is σ = 1532576763640. Its totient is φ = 1532383468776.
The previous prime is 1532480116183. The next prime is 1532480116249. The reversal of 1532480116207 is 7026110842351.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1532480116207 - 223 = 1532471727599 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1532480116207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1532480113207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48299928 + ... + 48331645.
It is an arithmetic number, because the mean of its divisors is an integer number (383144190910).
Almost surely, 21532480116207 is an apocalyptic number.
1532480116207 is a deficient number, since it is larger than the sum of its proper divisors (96647433).
1532480116207 is an equidigital number, since it uses as much as digits as its factorization.
1532480116207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96647432.
The product of its (nonzero) digits is 80640, while the sum is 40.
Adding to 1532480116207 its reverse (7026110842351), we get a palindrome (8558590958558).
The spelling of 1532480116207 in words is "one trillion, five hundred thirty-two billion, four hundred eighty million, one hundred sixteen thousand, two hundred seven".
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