Search a number
-
+
1532480116207 = 1585996631573
BaseRepresentation
bin10110010011001110111…
…011101101010111101111
312102111121011200222221111
4112103032323231113233
5200102004402204312
63132002303212451
7215501200026625
oct26231673552757
95374534628844
101532480116207
11540a1508a437
122090085a7127
13b1687568591
145425b22b515
1529ce3ac28a7
hex164ceeed5ef

1532480116207 has 4 divisors (see below), whose sum is σ = 1532576763640. Its totient is φ = 1532383468776.

The previous prime is 1532480116183. The next prime is 1532480116249. The reversal of 1532480116207 is 7026110842351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1532480116207 - 223 = 1532471727599 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1532480116207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1532480113207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48299928 + ... + 48331645.

It is an arithmetic number, because the mean of its divisors is an integer number (383144190910).

Almost surely, 21532480116207 is an apocalyptic number.

1532480116207 is a deficient number, since it is larger than the sum of its proper divisors (96647433).

1532480116207 is an equidigital number, since it uses as much as digits as its factorization.

1532480116207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96647432.

The product of its (nonzero) digits is 80640, while the sum is 40.

Adding to 1532480116207 its reverse (7026110842351), we get a palindrome (8558590958558).

The spelling of 1532480116207 in words is "one trillion, five hundred thirty-two billion, four hundred eighty million, one hundred sixteen thousand, two hundred seven".

Divisors: 1 15859 96631573 1532480116207