153250214241 has 4 divisors (see below), whose sum is σ = 204333618992. Its totient is φ = 102166809492.

The previous prime is 153250214233. The next prime is 153250214261. The reversal of 153250214241 is 142412052351.

153250214241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142412052351 = 3 ⋅47470684117.

It is not a de Polignac number, because 153250214241 - 2³ = 153250214233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 153250214199 and 153250214208.

It is not an unprimeable number, because it can be changed into a prime (153250214261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25541702371 + ... + 25541702376.

It is an arithmetic number, because the mean of its divisors is an integer number (51083404748).

Almost surely, 2^153250214241 is an apocalyptic number.

It is an amenable number.

153250214241 is a deficient number, since it is larger than the sum of its proper divisors (51083404751).

153250214241 is an equidigital number, since it uses as much as digits as its factorization.

153250214241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51083404750.

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 153250214241 its reverse (142412052351), we get a palindrome (295662266592).

The spelling of 153250214241 in words is "one hundred fifty-three billion, two hundred fifty million, two hundred fourteen thousand, two hundred forty-one".