Base | Representation |
---|---|
bin | 1000111010111101010… |
… | …0011000111010111111 |
3 | 112122121022112112012210 |
4 | 2032233110120322333 |
5 | 10002341343304434 |
6 | 154224205231503 |
7 | 14034024550014 |
oct | 2165724307277 |
9 | 478538475183 |
10 | 153265213119 |
11 | 59aaa243097 |
12 | 25854262593 |
13 | 115b6ba1a25 |
14 | 75bd2b370b |
15 | 3ec05aeee9 |
hex | 23af518ebf |
153265213119 has 4 divisors (see below), whose sum is σ = 204353617496. Its totient is φ = 102176808744.
The previous prime is 153265213111. The next prime is 153265213133. The reversal of 153265213119 is 911312562351.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 153265213119 - 23 = 153265213111 is a prime.
It is a super-2 number, since 2×1532652131192 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153265213111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25544202184 + ... + 25544202189.
It is an arithmetic number, because the mean of its divisors is an integer number (51088404374).
Almost surely, 2153265213119 is an apocalyptic number.
153265213119 is a deficient number, since it is larger than the sum of its proper divisors (51088404377).
153265213119 is an equidigital number, since it uses as much as digits as its factorization.
153265213119 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51088404376.
The product of its digits is 48600, while the sum is 39.
The spelling of 153265213119 in words is "one hundred fifty-three billion, two hundred sixty-five million, two hundred thirteen thousand, one hundred nineteen".
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