Base | Representation |
---|---|
bin | 1000111011000110000… |
… | …1011110111011100010 |
3 | 112122200220010122201112 |
4 | 2032301201132323202 |
5 | 10002430330400114 |
6 | 154232010103322 |
7 | 14034654125414 |
oct | 2166141367342 |
9 | 478626118645 |
10 | 153302200034 |
11 | 5a019105995 |
12 | 2586471ab42 |
13 | 115c1751c89 |
14 | 75c41809b4 |
15 | 3ec396913e |
hex | 23b185eee2 |
153302200034 has 4 divisors (see below), whose sum is σ = 229953300054. Its totient is φ = 76651100016.
The previous prime is 153302200033. The next prime is 153302200063. The reversal of 153302200034 is 430002203351.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 430002203351 = 7 ⋅61428886193.
It can be written as a sum of positive squares in only one way, i.e., 114546371809 + 38755828225 = 338447^2 + 196865^2 .
It is a junction number, because it is equal to n+sod(n) for n = 153302199982 and 153302200009.
It is not an unprimeable number, because it can be changed into a prime (153302200031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38325550007 + ... + 38325550010.
Almost surely, 2153302200034 is an apocalyptic number.
153302200034 is a deficient number, since it is larger than the sum of its proper divisors (76651100020).
153302200034 is an equidigital number, since it uses as much as digits as its factorization.
153302200034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76651100019.
The product of its (nonzero) digits is 2160, while the sum is 23.
Adding to 153302200034 its reverse (430002203351), we get a palindrome (583304403385).
The spelling of 153302200034 in words is "one hundred fifty-three billion, three hundred two million, two hundred thousand, thirty-four".
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