Base | Representation |
---|---|
bin | 1000111011001101111… |
… | …1110001011111011001 |
3 | 112122210012102121211212 |
4 | 2032303133301133121 |
5 | 10003012314244301 |
6 | 154235151432505 |
7 | 14035535412020 |
oct | 2166337613731 |
9 | 478705377755 |
10 | 153335306201 |
11 | 5a035868060 |
12 | 25873825735 |
13 | 115c8573a1c |
14 | 75c871b8b7 |
15 | 3ec68084bb |
hex | 23b37f17d9 |
153335306201 has 32 divisors (see below), whose sum is σ = 193401354240. Its totient is φ = 118089417600.
The previous prime is 153335306191. The next prime is 153335306203. The reversal of 153335306201 is 102603533351.
It is not a de Polignac number, because 153335306201 - 214 = 153335289817 is a prime.
It is a super-2 number, since 2×1533353062012 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153335306203) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29650346 + ... + 29655516.
It is an arithmetic number, because the mean of its divisors is an integer number (6043792320).
Almost surely, 2153335306201 is an apocalyptic number.
153335306201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
153335306201 is a deficient number, since it is larger than the sum of its proper divisors (40066048039).
153335306201 is a wasteful number, since it uses less digits than its factorization.
153335306201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9605.
The product of its (nonzero) digits is 24300, while the sum is 32.
Adding to 153335306201 its reverse (102603533351), we get a palindrome (255938839552).
The spelling of 153335306201 in words is "one hundred fifty-three billion, three hundred thirty-five million, three hundred six thousand, two hundred one".
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