153365004240055 has 8 divisors (see below), whose sum is σ = 185362019514000. Its totient is φ = 121809327108096.

The previous prime is 153365004240023. The next prime is 153365004240079. The reversal of 153365004240055 is 550042400563351.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 153365004240055 - 2⁵ = 153365004240023 is a prime.

It is a super-3 number, since 3×153365004240055³ (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 153365004239993 and 153365004240020.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110334534730 + ... + 110334536119.

It is an arithmetic number, because the mean of its divisors is an integer number (23170252439250).

Almost surely, 2^{153365004240055} is an apocalyptic number.

153365004240055 is a deficient number, since it is larger than the sum of its proper divisors (31997015273945).

153365004240055 is a wasteful number, since it uses less digits than its factorization.

153365004240055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 220669070993.

The product of its (nonzero) digits is 1080000, while the sum is 43.

The spelling of 153365004240055 in words is "one hundred fifty-three trillion, three hundred sixty-five billion, four million, two hundred forty thousand, fifty-five".