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15338052053 = 143910658827
BaseRepresentation
bin11100100100011100…
…00001100111010101
31110120221020202220222
432102032001213111
5222403020131203
611013551404125
71052043201632
oct162216014725
943527222828
1015338052053
116560a26585
122b80823645
1315a58aab5c
14a570a1189
155eb83d038
hex3923819d5

15338052053 has 4 divisors (see below), whose sum is σ = 15348712320. Its totient is φ = 15327391788.

The previous prime is 15338052047. The next prime is 15338052073. The reversal of 15338052053 is 35025083351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35025083351 = 109332044907.

It is a cyclic number.

It is not a de Polignac number, because 15338052053 - 212 = 15338047957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15338052073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5327975 + ... + 5330852.

It is an arithmetic number, because the mean of its divisors is an integer number (3837178080).

Almost surely, 215338052053 is an apocalyptic number.

It is an amenable number.

15338052053 is a deficient number, since it is larger than the sum of its proper divisors (10660267).

15338052053 is a wasteful number, since it uses less digits than its factorization.

15338052053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10660266.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 15338052053 in words is "fifteen billion, three hundred thirty-eight million, fifty-two thousand, fifty-three".

Divisors: 1 1439 10658827 15338052053