Base | Representation |
---|---|
bin | 1101111100111001110111… |
… | …1100000110110010000111 |
3 | 2000022111011102220220001002 |
4 | 3133032131330012302013 |
5 | 4002312233331241401 |
6 | 52343031045523515 |
7 | 3142163645355434 |
oct | 337163574066207 |
9 | 60274142826032 |
10 | 15339977993351 |
11 | 4984714734a00 |
12 | 1878ba771359b |
13 | 87372769704b |
14 | 3b065d2d6b8b |
15 | 1b906490ea6b |
hex | df39df06c87 |
15339977993351 has 12 divisors (see below), whose sum is σ = 16982602446600. Its totient is φ = 13845107657040.
The previous prime is 15339977993293. The next prime is 15339977993363.
15339977993351 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-15339977993351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15339977996351) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 456014396 + ... + 456048033.
It is an arithmetic number, because the mean of its divisors is an integer number (1415216870550).
Almost surely, 215339977993351 is an apocalyptic number.
15339977993351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
15339977993351 is a deficient number, since it is larger than the sum of its proper divisors (1642624453249).
15339977993351 is a wasteful number, since it uses less digits than its factorization.
15339977993351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 912062590 (or 912062579 counting only the distinct ones).
The product of its digits is 651015225, while the sum is 74.
The spelling of 15339977993351 in words is "fifteen trillion, three hundred thirty-nine billion, nine hundred seventy-seven million, nine hundred ninety-three thousand, three hundred fifty-one".
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