Base | Representation |
---|---|
bin | 10110010100101001100… |
… | …110101011100101100101 |
3 | 12102122112012010200200211 |
4 | 112110221212223211211 |
5 | 200113113320034113 |
6 | 3132413244135421 |
7 | 215553661112050 |
oct | 26245146534545 |
9 | 5378465120624 |
10 | 1534001330533 |
11 | 54162583a261 |
12 | 209371b37571 |
13 | b186a7778b9 |
14 | 54363293a97 |
15 | 29d8240cb3d |
hex | 165299ab965 |
1534001330533 has 16 divisors (see below), whose sum is σ = 1755949258624. Its totient is φ = 1312756009920.
The previous prime is 1534001330501. The next prime is 1534001330539. The reversal of 1534001330533 is 3350331004351.
It is a cyclic number.
It is not a de Polignac number, because 1534001330533 - 25 = 1534001330501 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1534001330495 and 1534001330504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1534001330539) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13578466 + ... + 13690972.
It is an arithmetic number, because the mean of its divisors is an integer number (109746828664).
Almost surely, 21534001330533 is an apocalyptic number.
It is an amenable number.
1534001330533 is a deficient number, since it is larger than the sum of its proper divisors (221947928091).
1534001330533 is a wasteful number, since it uses less digits than its factorization.
1534001330533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 115612.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 1534001330533 its reverse (3350331004351), we get a palindrome (4884332334884).
The spelling of 1534001330533 in words is "one trillion, five hundred thirty-four billion, one million, three hundred thirty thousand, five hundred thirty-three".
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