Search a number
-
+
153400213646123 = 156479803809909
BaseRepresentation
bin100010111000010001000101…
…001111100010101100101011
3202010010220202122022210020212
4202320101011033202230223
5130101302114143133443
61302131030231011335
744211541203652463
oct4270210517425453
9663126678283225
10153400213646123
1144972735516884
1215255ba5209b4b
13677976905b772
1429c4877a0aba3
1512b04591be618
hex8b84453e2b2b

153400213646123 has 4 divisors (see below), whose sum is σ = 153410017471680. Its totient is φ = 153390409820568.

The previous prime is 153400213646117. The next prime is 153400213646131. The reversal of 153400213646123 is 321646312004351.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 153400213646123 - 28 = 153400213645867 is a prime.

It is a super-2 number, since 2×1534002136461232 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (153400213646923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4901889308 + ... + 4901920601.

It is an arithmetic number, because the mean of its divisors is an integer number (38352504367920).

Almost surely, 2153400213646123 is an apocalyptic number.

153400213646123 is a deficient number, since it is larger than the sum of its proper divisors (9803825557).

153400213646123 is an equidigital number, since it uses as much as digits as its factorization.

153400213646123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9803825556.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 153400213646123 in words is "one hundred fifty-three trillion, four hundred billion, two hundred thirteen million, six hundred forty-six thousand, one hundred twenty-three".

Divisors: 1 15647 9803809909 153400213646123