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153411122320203 = 3112422620171681
BaseRepresentation
bin100010111000011011001111…
…011100110101001101001011
3202010011221220212220211212210
4202320123033130311031023
5130101441434303221303
61302140032513440203
744212405424111136
oct4270331734651513
9663157825824783
10153411122320203
1144977323148100
121525812a570063
13677a7b708b7b7
1429c51d070721d
1512b0896c1e203
hex8b86cf73534b

153411122320203 has 12 divisors (see below), whose sum is σ = 224833931334824. Its totient is φ = 92976437769600.

The previous prime is 153411122320189. The next prime is 153411122320229. The reversal of 153411122320203 is 302023221114351.

It is not a de Polignac number, because 153411122320203 - 25 = 153411122320171 is a prime.

It is a super-2 number, since 2×1534111223202032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (153411122324203) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 211310085478 + ... + 211310086203.

Almost surely, 2153411122320203 is an apocalyptic number.

153411122320203 is a deficient number, since it is larger than the sum of its proper divisors (71422809014621).

153411122320203 is a wasteful number, since it uses less digits than its factorization.

153411122320203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 422620171706 (or 422620171695 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 153411122320203 its reverse (302023221114351), we get a palindrome (455434343434554).

The spelling of 153411122320203 in words is "one hundred fifty-three trillion, four hundred eleven billion, one hundred twenty-two million, three hundred twenty thousand, two hundred three".

Divisors: 1 3 11 33 121 363 422620171681 1267860515043 4648821888491 13946465665473 51137040773401 153411122320203