Base | Representation |
---|---|
bin | 100010111000011011001111… |
… | …011100110101001101001011 |
3 | 202010011221220212220211212210 |
4 | 202320123033130311031023 |
5 | 130101441434303221303 |
6 | 1302140032513440203 |
7 | 44212405424111136 |
oct | 4270331734651513 |
9 | 663157825824783 |
10 | 153411122320203 |
11 | 44977323148100 |
12 | 1525812a570063 |
13 | 677a7b708b7b7 |
14 | 29c51d070721d |
15 | 12b0896c1e203 |
hex | 8b86cf73534b |
153411122320203 has 12 divisors (see below), whose sum is σ = 224833931334824. Its totient is φ = 92976437769600.
The previous prime is 153411122320189. The next prime is 153411122320229. The reversal of 153411122320203 is 302023221114351.
It is not a de Polignac number, because 153411122320203 - 25 = 153411122320171 is a prime.
It is a super-2 number, since 2×1534111223202032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153411122324203) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 211310085478 + ... + 211310086203.
Almost surely, 2153411122320203 is an apocalyptic number.
153411122320203 is a deficient number, since it is larger than the sum of its proper divisors (71422809014621).
153411122320203 is a wasteful number, since it uses less digits than its factorization.
153411122320203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 422620171706 (or 422620171695 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 153411122320203 its reverse (302023221114351), we get a palindrome (455434343434554).
The spelling of 153411122320203 in words is "one hundred fifty-three trillion, four hundred eleven billion, one hundred twenty-two million, three hundred twenty thousand, two hundred three".
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