Base | Representation |
---|---|
bin | 1000111011100011010… |
… | …0000011110100010111 |
3 | 112200000102021122202211 |
4 | 2032320310003310113 |
5 | 10003203133311411 |
6 | 154252055414251 |
7 | 14041000551046 |
oct | 2167064036427 |
9 | 480012248684 |
10 | 153424510231 |
11 | 5a0811553a3 |
12 | 25899684387 |
13 | 11610ba7585 |
14 | 75d64dc55d |
15 | 3ece579221 |
hex | 23b8d03d17 |
153424510231 has 4 divisors (see below), whose sum is σ = 153491774464. Its totient is φ = 153357246000.
The previous prime is 153424510139. The next prime is 153424510297. The reversal of 153424510231 is 132015424351.
153424510231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 153424510231 - 213 = 153424502039 is a prime.
It is a super-2 number, since 2×1534245102312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 153424510193 and 153424510202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153424510931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33628695 + ... + 33633256.
It is an arithmetic number, because the mean of its divisors is an integer number (38372943616).
Almost surely, 2153424510231 is an apocalyptic number.
153424510231 is a deficient number, since it is larger than the sum of its proper divisors (67264233).
153424510231 is an equidigital number, since it uses as much as digits as its factorization.
153424510231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67264232.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 153424510231 its reverse (132015424351), we get a palindrome (285439934582).
The spelling of 153424510231 in words is "one hundred fifty-three billion, four hundred twenty-four million, five hundred ten thousand, two hundred thirty-one".
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