Base | Representation |
---|---|
bin | 1000111011100111001… |
… | …1011101111110101111 |
3 | 112200001120120011012001 |
4 | 2032321303131332233 |
5 | 10003221412214323 |
6 | 154253451553131 |
7 | 14041262051263 |
oct | 2167163357657 |
9 | 480046504161 |
10 | 153441132463 |
11 | 5a08a578983 |
12 | 258a315b7a7 |
13 | 11614477408 |
14 | 75d87c80a3 |
15 | 3ed0c5e3ad |
hex | 23b9cddfaf |
153441132463 has 4 divisors (see below), whose sum is σ = 161516981560. Its totient is φ = 145365283368.
The previous prime is 153441132451. The next prime is 153441132487. The reversal of 153441132463 is 364231144351.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 364231144351 = 19 ⋅19170060229.
It is a cyclic number.
It is not a de Polignac number, because 153441132463 - 29 = 153441131951 is a prime.
It is a super-2 number, since 2×1534411324632 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153441130463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4037924520 + ... + 4037924557.
It is an arithmetic number, because the mean of its divisors is an integer number (40379245390).
Almost surely, 2153441132463 is an apocalyptic number.
153441132463 is a deficient number, since it is larger than the sum of its proper divisors (8075849097).
153441132463 is an equidigital number, since it uses as much as digits as its factorization.
153441132463 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8075849096.
The product of its digits is 103680, while the sum is 37.
The spelling of 153441132463 in words is "one hundred fifty-three billion, four hundred forty-one million, one hundred thirty-two thousand, four hundred sixty-three".
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