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153453540536441 = 166392275129607
BaseRepresentation
bin100010111001000010101111…
…110001011111000001111001
3202010100000102002021111102122
4202321002233301133001321
5130103140322334131231
61302211325555211025
744215436534025065
oct4271025761370171
9663300362244378
10153453540536441
114499331011a862
12152643a82a6a75
1367817b7137232
1429c7296116aa5
1512b1a2ab7977b
hex8b90afc5f079

153453540536441 has 4 divisors (see below), whose sum is σ = 153545815667712. Its totient is φ = 153361265405172.

The previous prime is 153453540536437. The next prime is 153453540536507. The reversal of 153453540536441 is 144635045354351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 153453540536441 - 22 = 153453540536437 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (153453540536041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46137563141 + ... + 46137566466.

It is an arithmetic number, because the mean of its divisors is an integer number (38386453916928).

Almost surely, 2153453540536441 is an apocalyptic number.

It is an amenable number.

153453540536441 is a deficient number, since it is larger than the sum of its proper divisors (92275131271).

153453540536441 is an equidigital number, since it uses as much as digits as its factorization.

153453540536441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92275131270.

The product of its (nonzero) digits is 25920000, while the sum is 53.

The spelling of 153453540536441 in words is "one hundred fifty-three trillion, four hundred fifty-three billion, five hundred forty million, five hundred thirty-six thousand, four hundred forty-one".

Divisors: 1 1663 92275129607 153453540536441