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15345412104021 = 35115137368007
BaseRepresentation
bin1101111101001110000111…
…0101100101111101010101
32000100000012011011022111020
43133103201311211331111
54002404400444312041
652345330205431353
73142445421503616
oct337234165457525
960300164138436
1015345412104021
114986a5309575a
12187a06356b559
138740b244b24c
143b0a16cbbc0d
151b9281a16866
hexdf4e1d65f55

15345412104021 has 4 divisors (see below), whose sum is σ = 20460549472032. Its totient is φ = 10230274736012.

The previous prime is 15345412104019. The next prime is 15345412104089. The reversal of 15345412104021 is 12040121454351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15345412104021 - 21 = 15345412104019 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15345412100021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2557568684001 + ... + 2557568684006.

It is an arithmetic number, because the mean of its divisors is an integer number (5115137368008).

Almost surely, 215345412104021 is an apocalyptic number.

It is an amenable number.

15345412104021 is a deficient number, since it is larger than the sum of its proper divisors (5115137368011).

15345412104021 is an equidigital number, since it uses as much as digits as its factorization.

15345412104021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5115137368010.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 15345412104021 its reverse (12040121454351), we get a palindrome (27385533558372).

The spelling of 15345412104021 in words is "fifteen trillion, three hundred forty-five billion, four hundred twelve million, one hundred four thousand, twenty-one".

Divisors: 1 3 5115137368007 15345412104021