Base | Representation |
---|---|
bin | 1000111011101100000… |
… | …0110010001101110001 |
3 | 112200002222200212121121 |
4 | 2032323000302031301 |
5 | 10003242104303213 |
6 | 154255454222241 |
7 | 14041626244465 |
oct | 2167300621561 |
9 | 480088625547 |
10 | 153461400433 |
11 | 5a09aa61570 |
12 | 258a9ab4981 |
13 | 116187227b3 |
14 | 75db3824a5 |
15 | 3ed291488d |
hex | 23bb032371 |
153461400433 has 8 divisors (see below), whose sum is σ = 167654720736. Its totient is φ = 139308460800.
The previous prime is 153461400419. The next prime is 153461400457. The reversal of 153461400433 is 334004164351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 153461400433 - 225 = 153427846001 is a prime.
It is a super-3 number, since 3×1534614004333 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153461400403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10087216 + ... + 10102417.
It is an arithmetic number, because the mean of its divisors is an integer number (20956840092).
Almost surely, 2153461400433 is an apocalyptic number.
It is an amenable number.
153461400433 is a deficient number, since it is larger than the sum of its proper divisors (14193320303).
153461400433 is a wasteful number, since it uses less digits than its factorization.
153461400433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20190335.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 153461400433 its reverse (334004164351), we get a palindrome (487465564784).
The spelling of 153461400433 in words is "one hundred fifty-three billion, four hundred sixty-one million, four hundred thousand, four hundred thirty-three".
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