Search a number
-
+
153531354021 = 351177118007
BaseRepresentation
bin1000111011111100101…
…1101000101110100101
3112200021212022212220020
42032333023220232211
510003413011312041
6154310433425353
714043435656013
oct2167713505645
9480255285806
10153531354021
115a1264a0751
122590940b259
131162a076156
1476067918b3
153ed8b31866
hex23bf2e8ba5

153531354021 has 4 divisors (see below), whose sum is σ = 204708472032. Its totient is φ = 102354236012.

The previous prime is 153531353993. The next prime is 153531354029. The reversal of 153531354021 is 120453135351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 153531354021 - 214 = 153531337637 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153531354029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25588559001 + ... + 25588559006.

It is an arithmetic number, because the mean of its divisors is an integer number (51177118008).

Almost surely, 2153531354021 is an apocalyptic number.

It is an amenable number.

153531354021 is a deficient number, since it is larger than the sum of its proper divisors (51177118011).

153531354021 is an equidigital number, since it uses as much as digits as its factorization.

153531354021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51177118010.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 153531354021 its reverse (120453135351), we get a palindrome (273984489372).

The spelling of 153531354021 in words is "one hundred fifty-three billion, five hundred thirty-one million, three hundred fifty-four thousand, twenty-one".

Divisors: 1 3 51177118007 153531354021