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153540234501 = 32712696887
BaseRepresentation
bin1000111011111110110…
…1100000110100000101
3112200022111001001121220
42032333231200310011
510003422300001001
6154311352030553
714043604313433
oct2167755406405
9480274031556
10153540234501
115a130506795
1225910392459
131162bb65284
147607a23d53
153ed97d7c36
hex23bfb60d05

153540234501 has 12 divisors (see below), whose sum is σ = 205478820576. Its totient is φ = 101982297240.

The previous prime is 153540234493. The next prime is 153540234503. The reversal of 153540234501 is 105432045351.

It is not a de Polignac number, because 153540234501 - 23 = 153540234493 is a prime.

It is a super-2 number, since 2×1535402345012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153540234503) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 128121 + ... + 568766.

It is an arithmetic number, because the mean of its divisors is an integer number (17123235048).

Almost surely, 2153540234501 is an apocalyptic number.

It is an amenable number.

153540234501 is a deficient number, since it is larger than the sum of its proper divisors (51938586075).

153540234501 is an frugal number, since it uses more digits than its factorization.

153540234501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 697432 (or 697161 counting only the distinct ones).

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 153540234501 its reverse (105432045351), we get a palindrome (258972279852).

The spelling of 153540234501 in words is "one hundred fifty-three billion, five hundred forty million, two hundred thirty-four thousand, five hundred one".

Divisors: 1 3 271 813 73441 220323 696887 2090661 188856377 566569131 51180078167 153540234501