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15400456943117 = 31798348431699
BaseRepresentation
bin1110000000011011001011…
…0000111111011000001101
32000112021021022201212100112
43200012302300333120031
54004310113434134432
652430512223405405
73146434452065231
oct340066260773015
960467238655315
1015400456943117
1149a832a501014
121888865a53865
13879345418b5c
143b35596225c1
151ba90421d7b2
hexe01b2c3f60d

15400456943117 has 4 divisors (see below), whose sum is σ = 15400505692800. Its totient is φ = 15400408193436.

The previous prime is 15400456942943. The next prime is 15400456943149. The reversal of 15400456943117 is 71134965400451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15400456943117 is a prime.

It is a super-2 number, since 2×154004569431172 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15400456943317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23897867 + ... + 24533832.

It is an arithmetic number, because the mean of its divisors is an integer number (3850126423200).

Almost surely, 215400456943117 is an apocalyptic number.

It is an amenable number.

15400456943117 is a deficient number, since it is larger than the sum of its proper divisors (48749683).

15400456943117 is an equidigital number, since it uses as much as digits as its factorization.

15400456943117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48749682.

The product of its (nonzero) digits is 1814400, while the sum is 50.

The spelling of 15400456943117 in words is "fifteen trillion, four hundred billion, four hundred fifty-six million, nine hundred forty-three thousand, one hundred seventeen".

Divisors: 1 317983 48431699 15400456943117