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1540113000000 = 26356513371
BaseRepresentation
bin10110011010010101111…
…000110110011001000000
312110020022010022200002020
4112122111320312121000
5200213122412000000
63135303530321440
7216161302334301
oct26322570663100
95406263280066
101540113000000
11544181701a63
1220a598889280
13b2302a11873
1454782c507a8
152a0ddc52ba0
hex16695e36640

1540113000000 has 196 divisors, whose sum is σ = 5093547614256. Its totient is φ = 410696000000.

The previous prime is 1540112999977. The next prime is 1540113000043. The reversal of 1540113000000 is 3110451.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 2743315 + ... + 3256685.

Almost surely, 21540113000000 is an apocalyptic number.

1540113000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1540113000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2546773807128).

1540113000000 is an abundant number, since it is smaller than the sum of its proper divisors (3553434614256).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1540113000000 is an frugal number, since it uses more digits than its factorization.

1540113000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 513416 (or 513381 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 1540113000000 its reverse (3110451), we get a palindrome (1540116110451).

The spelling of 1540113000000 in words is "one trillion, five hundred forty billion, one hundred thirteen million", and thus it is an aban number.