1540440331313 has 4 divisors (see below), whose sum is σ = 1658935741428. Its totient is φ = 1421944921200.

The previous prime is 1540440331303. The next prime is 1540440331327. The reversal of 1540440331313 is 3131330440451.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 367663960609 + 1172776370704 = 606353^2 + 1082948^2 .

It is a cyclic number.

It is not a de Polignac number, because 1540440331313 - 2¹⁴ = 1540440314929 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1540440331313.

It is not an unprimeable number, because it can be changed into a prime (1540440331303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59247705038 + ... + 59247705063.

It is an arithmetic number, because the mean of its divisors is an integer number (414733935357).

Almost surely, 2^{1540440331313} is an apocalyptic number.

1540440331313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1540440331313 is a deficient number, since it is larger than the sum of its proper divisors (118495410115).

1540440331313 is a wasteful number, since it uses less digits than its factorization.

1540440331313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118495410114.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 1540440331313 its reverse (3131330440451), we get a palindrome (4671770771764).

The spelling of 1540440331313 in words is "one trillion, five hundred forty billion, four hundred forty million, three hundred thirty-one thousand, three hundred thirteen".