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154055013223 = 1259122362997
BaseRepresentation
bin1000111101111001100…
…1001111001101100111
3112201122100200112021111
42033132121033031213
510011001040410343
6154434421325451
714062425002146
oct2173631171547
9481570615244
10154055013223
115a375047651
1225a34866887
13116b16c3077
14765614575d
154019abec9d
hex23de64f367

154055013223 has 4 divisors (see below), whose sum is σ = 154177377480. Its totient is φ = 153932648968.

The previous prime is 154055013209. The next prime is 154055013241. The reversal of 154055013223 is 322310550451.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 154055013223 - 221 = 154052916071 is a prime.

It is a super-4 number, since 4×1540550132234 (a number of 46 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (154055013283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61180240 + ... + 61182757.

It is an arithmetic number, because the mean of its divisors is an integer number (38544344370).

Almost surely, 2154055013223 is an apocalyptic number.

154055013223 is a deficient number, since it is larger than the sum of its proper divisors (122364257).

154055013223 is a wasteful number, since it uses less digits than its factorization.

154055013223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122364256.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 154055013223 its reverse (322310550451), we get a palindrome (476365563674).

The spelling of 154055013223 in words is "one hundred fifty-four billion, fifty-five million, thirteen thousand, two hundred twenty-three".

Divisors: 1 1259 122362997 154055013223