Base | Representation |
---|---|
bin | 100011000010101001001010… |
… | …011000000110010011101111 |
3 | 202012200002021101000110002111 |
4 | 203002221022120012103233 |
5 | 130144442431133040401 |
6 | 1303434353430104451 |
7 | 44314213233625642 |
oct | 4302511230062357 |
9 | 665602241013074 |
10 | 154113264346351 |
11 | 45118082aa9742 |
12 | 153502244ab127 |
13 | 67cba8423c41b |
14 | 2a0b19c2b7a59 |
15 | 12c3c8dd90e51 |
hex | 8c2a4a6064ef |
154113264346351 has 4 divisors (see below), whose sum is σ = 154113540251400. Its totient is φ = 154112988441304.
The previous prime is 154113264346343. The next prime is 154113264346409. The reversal of 154113264346351 is 153643462311451.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 154113264346351 - 23 = 154113264346343 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 154113264346295 and 154113264346304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (154113264347351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137112961 + ... + 138232378.
It is an arithmetic number, because the mean of its divisors is an integer number (38528385062850).
Almost surely, 2154113264346351 is an apocalyptic number.
154113264346351 is a deficient number, since it is larger than the sum of its proper divisors (275905049).
154113264346351 is an equidigital number, since it uses as much as digits as its factorization.
154113264346351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 275905048.
The product of its digits is 3110400, while the sum is 49.
The spelling of 154113264346351 in words is "one hundred fifty-four trillion, one hundred thirteen billion, two hundred sixty-four million, three hundred forty-six thousand, three hundred fifty-one".
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