Base | Representation |
---|---|
bin | 1000111110000111111… |
… | …0001001100110101111 |
3 | 112201210112121020210022 |
4 | 2033201332021212233 |
5 | 10011111421134411 |
6 | 154444403432355 |
7 | 14064054031463 |
oct | 2174176114657 |
9 | 481715536708 |
10 | 154115021231 |
11 | 5a3a5a03546 |
12 | 25a509856bb |
13 | 116c0c73872 |
14 | 76600c64a3 |
15 | 401eec4edb |
hex | 23e1f899af |
154115021231 has 4 divisors (see below), whose sum is σ = 160815674352. Its totient is φ = 147414368112.
The previous prime is 154115021219. The next prime is 154115021239. The reversal of 154115021231 is 132120511451.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 154115021231 - 214 = 154115004847 is a prime.
It is a super-2 number, since 2×1541150212312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 154115021231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (154115021239) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3350326526 + ... + 3350326571.
It is an arithmetic number, because the mean of its divisors is an integer number (40203918588).
Almost surely, 2154115021231 is an apocalyptic number.
154115021231 is a deficient number, since it is larger than the sum of its proper divisors (6700653121).
154115021231 is an equidigital number, since it uses as much as digits as its factorization.
154115021231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6700653120.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 154115021231 its reverse (132120511451), we get a palindrome (286235532682).
The spelling of 154115021231 in words is "one hundred fifty-four billion, one hundred fifteen million, twenty-one thousand, two hundred thirty-one".
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