Base | Representation |
---|---|
bin | 10110011100010100000… |
… | …100111111101101011011 |
3 | 12110102202200001011022002 |
4 | 112130110010333231123 |
5 | 200231441402104430 |
6 | 3140253555351215 |
7 | 216264620444606 |
oct | 26342404775533 |
9 | 5412680034262 |
10 | 1542230113115 |
11 | 54506876941a |
12 | 20aa898b250b |
13 | b257c511b13 |
14 | 549040b333d |
15 | 2a1b4a4a845 |
hex | 1671413fb5b |
1542230113115 has 4 divisors (see below), whose sum is σ = 1850676135744. Its totient is φ = 1233784090488.
The previous prime is 1542230113079. The next prime is 1542230113121. The reversal of 1542230113115 is 5113110322451.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1542230113115 - 28 = 1542230112859 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154223011307 + ... + 154223011316.
It is an arithmetic number, because the mean of its divisors is an integer number (462669033936).
Almost surely, 21542230113115 is an apocalyptic number.
1542230113115 is a deficient number, since it is larger than the sum of its proper divisors (308446022629).
1542230113115 is an equidigital number, since it uses as much as digits as its factorization.
1542230113115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 308446022628.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 1542230113115 its reverse (5113110322451), we get a palindrome (6655340435566).
The spelling of 1542230113115 in words is "one trillion, five hundred forty-two billion, two hundred thirty million, one hundred thirteen thousand, one hundred fifteen".
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