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1542424135301 = 7415374300123
BaseRepresentation
bin10110011100011111101…
…001001000011010000101
312110110021012010111200222
4112130133221020122011
5200232341034312201
63140325130114125
7216302464554140
oct26343751103205
95413235114628
101542424135301
11545158239135
1220ab2287b945
13b25b078524a
1454921b7b057
152a1c6ac391b
hex1671fa48685

1542424135301 has 8 divisors (see below), whose sum is σ = 1805764841664. Its totient is φ = 1289832029280.

The previous prime is 1542424135253. The next prime is 1542424135309. The reversal of 1542424135301 is 1035314242451.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1542424135301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1542424135309) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2687149775 + ... + 2687150348.

It is an arithmetic number, because the mean of its divisors is an integer number (225720605208).

Almost surely, 21542424135301 is an apocalyptic number.

It is an amenable number.

1542424135301 is a deficient number, since it is larger than the sum of its proper divisors (263340706363).

1542424135301 is an equidigital number, since it uses as much as digits as its factorization.

1542424135301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5374300171.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 1542424135301 its reverse (1035314242451), we get a palindrome (2577738377752).

The spelling of 1542424135301 in words is "one trillion, five hundred forty-two billion, four hundred twenty-four million, one hundred thirty-five thousand, three hundred one".

Divisors: 1 7 41 287 5374300123 37620100861 220346305043 1542424135301