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1543404513442 = 21126377704601
BaseRepresentation
bin10110011101011010000…
…100111110100010100010
312110112210111212212200111
4112131122010332202202
5200241343023412232
63141010311041534
7216336000622351
oct26353204764242
95415714785614
101543404513442
1154561067a800
1220b1570702aa
13b270891215c
14549b605b998
152a232bcb047
hex1675a13e8a2

1543404513442 has 12 divisors (see below), whose sum is σ = 2544704136198. Its totient is φ = 701547506000.

The previous prime is 1543404513407. The next prime is 1543404513491. The reversal of 1543404513442 is 2443154043451.

It can be written as a sum of positive squares in only one way, i.e., 1528385765841 + 15018747601 = 1236279^2 + 122551^2 .

It is a super-2 number, since 2×15434045134422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1543404513395 and 1543404513404.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3188852059 + ... + 3188852542.

Almost surely, 21543404513442 is an apocalyptic number.

1543404513442 is a deficient number, since it is larger than the sum of its proper divisors (1001299622756).

1543404513442 is a wasteful number, since it uses less digits than its factorization.

1543404513442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6377704625 (or 6377704614 counting only the distinct ones).

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 1543404513442 its reverse (2443154043451), we get a palindrome (3986558556893).

The spelling of 1543404513442 in words is "one trillion, five hundred forty-three billion, four hundred four million, five hundred thirteen thousand, four hundred forty-two".

Divisors: 1 2 11 22 121 242 6377704601 12755409202 70154750611 140309501222 771702256721 1543404513442