Base | Representation |
---|---|
bin | 10110011101011010100… |
… | …111000101000100101111 |
3 | 12110112211010201001121001 |
4 | 112131122213011010233 |
5 | 200241402320444403 |
6 | 3141011230421131 |
7 | 216336136614454 |
oct | 26353247050457 |
9 | 5415733631531 |
10 | 1543413453103 |
11 | 545615726255 |
12 | 20b15a0617a7 |
13 | b270a7221b2 |
14 | 549b730782b |
15 | 2a233894c1d |
hex | 1675a9c512f |
1543413453103 has 4 divisors (see below), whose sum is σ = 1550334589888. Its totient is φ = 1536492316320.
The previous prime is 1543413453077. The next prime is 1543413453149. The reversal of 1543413453103 is 3013543143451.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1543413453103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1543413153103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3460568058 + ... + 3460568503.
It is an arithmetic number, because the mean of its divisors is an integer number (387583647472).
Almost surely, 21543413453103 is an apocalyptic number.
1543413453103 is a deficient number, since it is larger than the sum of its proper divisors (6921136785).
1543413453103 is an equidigital number, since it uses as much as digits as its factorization.
1543413453103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6921136784.
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 1543413453103 its reverse (3013543143451), we get a palindrome (4556956596554).
The spelling of 1543413453103 in words is "one trillion, five hundred forty-three billion, four hundred thirteen million, four hundred fifty-three thousand, one hundred three".
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