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1550157165511 = 5506128153451
BaseRepresentation
bin10110100011101100100…
…100010011001111000111
312111012020010012010220021
4112203230210103033013
5200344210213244021
63144044331520011
7216665224333543
oct26435444231707
95435203163807
101550157165511
11548466342199
122105205b9007
13b32438c3876
1455056bcca23
152a4ca936c41
hex168ec9133c7

1550157165511 has 4 divisors (see below), whose sum is σ = 1550185374024. Its totient is φ = 1550128957000.

The previous prime is 1550157165509. The next prime is 1550157165539. The reversal of 1550157165511 is 1155617510551.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1550157165511 - 21 = 1550157165509 is a prime.

It is a super-2 number, since 2×15501571655112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1550157165551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14021665 + ... + 14131786.

It is an arithmetic number, because the mean of its divisors is an integer number (387546343506).

Almost surely, 21550157165511 is an apocalyptic number.

1550157165511 is a deficient number, since it is larger than the sum of its proper divisors (28208513).

1550157165511 is an equidigital number, since it uses as much as digits as its factorization.

1550157165511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28208512.

The product of its (nonzero) digits is 131250, while the sum is 43.

The spelling of 1550157165511 in words is "one trillion, five hundred fifty billion, one hundred fifty-seven million, one hundred sixty-five thousand, five hundred eleven".

Divisors: 1 55061 28153451 1550157165511