Base | Representation |
---|---|
bin | 10110100011110101001… |
… | …101010110101000010001 |
3 | 12111012121012222212102111 |
4 | 112203311031112220101 |
5 | 200400004322120131 |
6 | 3144110551145321 |
7 | 220001634543436 |
oct | 26436515265021 |
9 | 5435535885374 |
10 | 1550302145041 |
11 | 548530165491 |
12 | 210561075241 |
13 | b3267955580 |
14 | 5506c16bb8d |
15 | 2a4d8523ab1 |
hex | 168f5356a11 |
1550302145041 has 32 divisors (see below), whose sum is σ = 1770438118400. Its totient is φ = 1345727234880.
The previous prime is 1550302144997. The next prime is 1550302145083. The reversal of 1550302145041 is 1405412030551.
It is a cyclic number.
It is not a de Polignac number, because 1550302145041 - 213 = 1550302136849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1550302144994 and 1550302145012.
It is not an unprimeable number, because it can be changed into a prime (1550302145141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19713100 + ... + 19791586.
It is an arithmetic number, because the mean of its divisors is an integer number (55326191200).
Almost surely, 21550302145041 is an apocalyptic number.
It is an amenable number.
1550302145041 is a deficient number, since it is larger than the sum of its proper divisors (220135973359).
1550302145041 is a wasteful number, since it uses less digits than its factorization.
1550302145041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79109.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 1550302145041 its reverse (1405412030551), we get a palindrome (2955714175592).
The spelling of 1550302145041 in words is "one trillion, five hundred fifty billion, three hundred two million, one hundred forty-five thousand, forty-one".
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