Base | Representation |
---|---|
bin | 10110100100011111000… |
… | …110101111000100111011 |
3 | 12111021102012122022012121 |
4 | 112210133012233010323 |
5 | 200402424243200433 |
6 | 3144304421022111 |
7 | 220025231266462 |
oct | 26443706570473 |
9 | 5437365568177 |
10 | 1551005053243 |
11 | 548860a10858 |
12 | 210718554937 |
13 | b334a472599 |
14 | 550d76619d9 |
15 | 2a52a0bcc2d |
hex | 1691f1af13b |
1551005053243 has 4 divisors (see below), whose sum is σ = 1551008327488. Its totient is φ = 1551001779000.
The previous prime is 1551005053223. The next prime is 1551005053277. The reversal of 1551005053243 is 3423505001551.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1551005053243 - 29 = 1551005052731 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1551005053199 and 1551005053208.
It is not an unprimeable number, because it can be changed into a prime (1551005053223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 775371 + ... + 1924372.
It is an arithmetic number, because the mean of its divisors is an integer number (387752081872).
Almost surely, 21551005053243 is an apocalyptic number.
1551005053243 is a deficient number, since it is larger than the sum of its proper divisors (3274245).
1551005053243 is an equidigital number, since it uses as much as digits as its factorization.
1551005053243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3274244.
The product of its (nonzero) digits is 45000, while the sum is 34.
The spelling of 1551005053243 in words is "one trillion, five hundred fifty-one billion, five million, fifty-three thousand, two hundred forty-three".
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