Base | Representation |
---|---|
bin | 100011010001011000011100… |
… | …001110100001100110100111 |
3 | 202100020220120210102212122010 |
4 | 203101120130032201212213 |
5 | 130313041224201213011 |
6 | 1305531540404005303 |
7 | 44450330300016354 |
oct | 4321303416414647 |
9 | 670226523385563 |
10 | 155126102366631 |
11 | 45478679725250 |
12 | 15494589990833 |
13 | 6873437175066 |
14 | 2a4420176362b |
15 | 12e02bc7101a6 |
hex | 8d161c3a19a7 |
155126102366631 has 16 divisors (see below), whose sum is σ = 225645398903808. Its totient is φ = 94012723022400.
The previous prime is 155126102366617. The next prime is 155126102366647. The reversal of 155126102366631 is 136663201621551.
It is not a de Polignac number, because 155126102366631 - 218 = 155126102104487 is a prime.
It is a super-2 number, since 2×1551261023666312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (155126102361631) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76397550 + ... + 78401771.
It is an arithmetic number, because the mean of its divisors is an integer number (14102837431488).
Almost surely, 2155126102366631 is an apocalyptic number.
155126102366631 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
155126102366631 is a deficient number, since it is larger than the sum of its proper divisors (70519296537177).
155126102366631 is a wasteful number, since it uses less digits than its factorization.
155126102366631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154829702.
The product of its (nonzero) digits is 1166400, while the sum is 48.
The spelling of 155126102366631 in words is "one hundred fifty-five trillion, one hundred twenty-six billion, one hundred two million, three hundred sixty-six thousand, six hundred thirty-one".
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