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155144441551 = 1114104040141
BaseRepresentation
bin1001000001111101010…
…1000100111011001111
3112211110021122012222211
42100133111010323033
510020213434112201
6155134455451251
714131423665061
oct2203725047317
9484407565884
10155144441551
115a883aa1240
1226099686b27
1311826311c08
14771aad1731
154080568651
hex241f544ecf

155144441551 has 4 divisors (see below), whose sum is σ = 169248481704. Its totient is φ = 141040401400.

The previous prime is 155144441531. The next prime is 155144441603.

155144441551 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 155144441551 - 219 = 155143917263 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155144441531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7052020060 + ... + 7052020081.

It is an arithmetic number, because the mean of its divisors is an integer number (42312120426).

Almost surely, 2155144441551 is an apocalyptic number.

155144441551 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

155144441551 is a deficient number, since it is larger than the sum of its proper divisors (14104040153).

155144441551 is a wasteful number, since it uses less digits than its factorization.

155144441551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14104040152.

The product of its digits is 160000, while the sum is 40.

It can be divided in two parts, 155144 and 441551, that added together give a palindrome (596695).

The spelling of 155144441551 in words is "one hundred fifty-five billion, one hundred forty-four million, four hundred forty-one thousand, five hundred fifty-one".

Divisors: 1 11 14104040141 155144441551