Base | Representation |
---|---|
bin | 11100111011011110… |
… | …10111010110101111 |
3 | 1111002101221212211102 |
4 | 32131233113112233 |
5 | 223302010404411 |
6 | 11045054313315 |
7 | 1056611136140 |
oct | 163557272657 |
9 | 44071855742 |
10 | 15531341231 |
11 | 66500455aa |
12 | 30154b883b |
13 | 1606955753 |
14 | a74a17ac7 |
15 | 60d7bdd3b |
hex | 39dbd75af |
15531341231 has 4 divisors (see below), whose sum is σ = 17750104272. Its totient is φ = 13312578192.
The previous prime is 15531341213. The next prime is 15531341233. The reversal of 15531341231 is 13214313551.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15531341231 is a prime.
It is a super-2 number, since 2×155313412312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15531341194 and 15531341203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15531341233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1109381510 + ... + 1109381523.
It is an arithmetic number, because the mean of its divisors is an integer number (4437526068).
Almost surely, 215531341231 is an apocalyptic number.
15531341231 is a deficient number, since it is larger than the sum of its proper divisors (2218763041).
15531341231 is an equidigital number, since it uses as much as digits as its factorization.
15531341231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2218763040.
The product of its digits is 5400, while the sum is 29.
Adding to 15531341231 its reverse (13214313551), we get a palindrome (28745654782).
The spelling of 15531341231 in words is "fifteen billion, five hundred thirty-one million, three hundred forty-one thousand, two hundred thirty-one".
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