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1553355131143 = 10537314741491
BaseRepresentation
bin10110100110101011001…
…011100100100100000111
312111111110222201122000211
4112212223023210210013
5200422232403144033
63145333531220251
7220140405521524
oct26465313444407
95444428648024
101553355131143
115498575260a2
122110735a7687
13b36332cc41a
145527b80814b
152a6165822cd
hex169ab2e4907

1553355131143 has 4 divisors (see below), whose sum is σ = 1553369978008. Its totient is φ = 1553340284280.

The previous prime is 1553355131137. The next prime is 1553355131173. The reversal of 1553355131143 is 3411315533551.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1553355131143 - 213 = 1553355122951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1553355131096 and 1553355131105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1553355131113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7265373 + ... + 7476118.

It is an arithmetic number, because the mean of its divisors is an integer number (388342494502).

Almost surely, 21553355131143 is an apocalyptic number.

1553355131143 is a deficient number, since it is larger than the sum of its proper divisors (14846865).

1553355131143 is a wasteful number, since it uses less digits than its factorization.

1553355131143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14846864.

The product of its digits is 202500, while the sum is 40.

The spelling of 1553355131143 in words is "one trillion, five hundred fifty-three billion, three hundred fifty-five million, one hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 105373 14741491 1553355131143