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155354013253 = 1346311539331
BaseRepresentation
bin1001000010101111010…
…0100001111001000101
3112211222212222120022201
42100223310201321011
510021131111411003
6155211343354501
714136550216225
oct2205364417105
9484885876281
10155354013253
115a98132159a
12261378b2a31
131185a86ab3a
14773a886085
154093b63b1d
hex242bd21e45

155354013253 has 4 divisors (see below), whose sum is σ = 155365566048. Its totient is φ = 155342460460.

The previous prime is 155354013223. The next prime is 155354013299. The reversal of 155354013253 is 352310453551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 352310453551 = 750330064793.

It is a cyclic number.

It is not a de Polignac number, because 155354013253 - 29 = 155354012741 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155354013223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5756203 + ... + 5783128.

It is an arithmetic number, because the mean of its divisors is an integer number (38841391512).

Almost surely, 2155354013253 is an apocalyptic number.

It is an amenable number.

155354013253 is a deficient number, since it is larger than the sum of its proper divisors (11552795).

155354013253 is a wasteful number, since it uses less digits than its factorization.

155354013253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11552794.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 155354013253 in words is "one hundred fifty-five billion, three hundred fifty-four million, thirteen thousand, two hundred fifty-three".

Divisors: 1 13463 11539331 155354013253