Base | Representation |
---|---|
bin | 10110101000010000010… |
… | …110101101011110001111 |
3 | 12111122212021201110000001 |
4 | 112220100112231132033 |
5 | 200434221423100111 |
6 | 3150214204545131 |
7 | 220230436403611 |
oct | 26502026553617 |
9 | 5448767643001 |
10 | 1555052550031 |
11 | 54a548696022 |
12 | 211467b521a7 |
13 | b3843b83bb6 |
14 | 5539d01adb1 |
15 | 2a6b55c61c1 |
hex | 16a105ad78f |
1555052550031 has 4 divisors (see below), whose sum is σ = 1555055045064. Its totient is φ = 1555050055000.
The previous prime is 1555052550017. The next prime is 1555052550041. The reversal of 1555052550031 is 1300552505551.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 1555052550031 - 213 = 1555052541839 is a prime.
It is a super-2 number, since 2×15550525500312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1555052550041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570861 + ... + 1853641.
It is an arithmetic number, because the mean of its divisors is an integer number (388763761266).
Almost surely, 21555052550031 is an apocalyptic number.
1555052550031 is a deficient number, since it is larger than the sum of its proper divisors (2495033).
1555052550031 is a wasteful number, since it uses less digits than its factorization.
1555052550031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2495032.
The product of its (nonzero) digits is 93750, while the sum is 37.
The spelling of 1555052550031 in words is "one trillion, five hundred fifty-five billion, fifty-two million, five hundred fifty thousand, thirty-one".
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