Base | Representation |
---|---|
bin | 1001000011010100111… |
… | …1101111001000101011 |
3 | 112212101220112020220011 |
4 | 2100311033233020223 |
5 | 10021442101442311 |
6 | 155235152512351 |
7 | 14143510245142 |
oct | 2206517571053 |
9 | 485356466804 |
10 | 155512140331 |
11 | 5aa52604829 |
12 | 2618084b6b7 |
13 | 11884553c62 |
14 | 7753888759 |
15 | 40a299b321 |
hex | 24353ef22b |
155512140331 has 4 divisors (see below), whose sum is σ = 158446331712. Its totient is φ = 152577948952.
The previous prime is 155512140319. The next prime is 155512140341. The reversal of 155512140331 is 133041215551.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 155512140331 - 25 = 155512140299 is a prime.
It is a super-2 number, since 2×1555121403312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 155512140293 and 155512140302.
It is not an unprimeable number, because it can be changed into a prime (155512140341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1467095611 + ... + 1467095716.
It is an arithmetic number, because the mean of its divisors is an integer number (39611582928).
Almost surely, 2155512140331 is an apocalyptic number.
155512140331 is a deficient number, since it is larger than the sum of its proper divisors (2934191381).
155512140331 is an equidigital number, since it uses as much as digits as its factorization.
155512140331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2934191380.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 155512140331 its reverse (133041215551), we get a palindrome (288553355882).
The spelling of 155512140331 in words is "one hundred fifty-five billion, five hundred twelve million, one hundred forty thousand, three hundred thirty-one".
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