Base | Representation |
---|---|
bin | 10110101000100101000… |
… | …111101101011100110101 |
3 | 12111200202120021110020221 |
4 | 112220211013231130311 |
5 | 200440430120024232 |
6 | 3150312532054341 |
7 | 220242166562041 |
oct | 26504507553465 |
9 | 5450676243227 |
10 | 1555400939317 |
11 | 54a707310055 |
12 | 2115447643b1 |
13 | b389b0c4bc4 |
14 | 553d33c9021 |
15 | 2a6d5e92897 |
hex | 16a251ed735 |
1555400939317 has 16 divisors (see below), whose sum is σ = 1652550854400. Its totient is φ = 1458887772160.
The previous prime is 1555400939311. The next prime is 1555400939333. The reversal of 1555400939317 is 7139390045551.
It is a cyclic number.
It is not a de Polignac number, because 1555400939317 - 27 = 1555400939189 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1555400939311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5871909 + ... + 6131077.
It is an arithmetic number, because the mean of its divisors is an integer number (103284428400).
Almost surely, 21555400939317 is an apocalyptic number.
1555400939317 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
1555400939317 is a deficient number, since it is larger than the sum of its proper divisors (97149915083).
1555400939317 is a wasteful number, since it uses less digits than its factorization.
1555400939317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260396.
The product of its (nonzero) digits is 2551500, while the sum is 52.
The spelling of 1555400939317 in words is "one trillion, five hundred fifty-five billion, four hundred million, nine hundred thirty-nine thousand, three hundred seventeen".
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