Base | Representation |
---|---|
bin | 100011101111101100111010… |
… | …001110111110010010101010 |
3 | 202121122002121212000020101112 |
4 | 203233230322032332102222 |
5 | 131101210343211023203 |
6 | 1314205042324550322 |
7 | 45054011023456055 |
oct | 4357547216762252 |
9 | 677562555006345 |
10 | 157209664939178 |
11 | 46101276457645 |
12 | 157703528523a2 |
13 | 6994a66948717 |
14 | 2ab6dba197a9c |
15 | 13295b68286d8 |
hex | 8efb3a3be4aa |
157209664939178 has 4 divisors (see below), whose sum is σ = 235814497408770. Its totient is φ = 78604832469588.
The previous prime is 157209664939157. The next prime is 157209664939213. The reversal of 157209664939178 is 871939466902751.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 154061393149609 + 3148271789569 = 12412147^2 + 1774337^2 .
It is a super-2 number, since 2×1572096649391782 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 157209664939099 and 157209664939108.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39302416234793 + ... + 39302416234796.
It is a 1-persistent number, because it is pandigital, but 2⋅157209664939178 = 314419329878356 is not.
Almost surely, 2157209664939178 is an apocalyptic number.
157209664939178 is a deficient number, since it is larger than the sum of its proper divisors (78604832469592).
157209664939178 is an equidigital number, since it uses as much as digits as its factorization.
157209664939178 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78604832469591.
The product of its (nonzero) digits is 1234517760, while the sum is 77.
The spelling of 157209664939178 in words is "one hundred fifty-seven trillion, two hundred nine billion, six hundred sixty-four million, nine hundred thirty-nine thousand, one hundred seventy-eight".
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