Base | Representation |
---|---|
bin | 100100011010000000000011… |
… | …010111101001010100101111 |
3 | 202222220222111211002000120021 |
4 | 210122000003113221110233 |
5 | 131441321430423400403 |
6 | 1324312250441103011 |
7 | 45504013403206060 |
oct | 4432000327512457 |
9 | 688828454060507 |
10 | 160116437325103 |
11 | 47021aaa708a86 |
12 | 15b5b77aa87a67 |
13 | 6b45bb8a6982c |
14 | 2b7796965a567 |
15 | 1379ee168a8bd |
hex | 91a0035e952f |
160116437325103 has 4 divisors (see below), whose sum is σ = 182990214085840. Its totient is φ = 137242660564368.
The previous prime is 160116437325101. The next prime is 160116437325157. The reversal of 160116437325103 is 301523734611061.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 160116437325103 - 21 = 160116437325101 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 160116437325103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (160116437325101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11436888380358 + ... + 11436888380371.
It is an arithmetic number, because the mean of its divisors is an integer number (45747553521460).
Almost surely, 2160116437325103 is an apocalyptic number.
160116437325103 is a deficient number, since it is larger than the sum of its proper divisors (22873776760737).
160116437325103 is an equidigital number, since it uses as much as digits as its factorization.
160116437325103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22873776760736.
The product of its (nonzero) digits is 272160, while the sum is 43.
The spelling of 160116437325103 in words is "one hundred sixty trillion, one hundred sixteen billion, four hundred thirty-seven million, three hundred twenty-five thousand, one hundred three".
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