16013403533 has 4 divisors (see below), whose sum is σ = 16024533120. Its totient is φ = 16002273948.

The previous prime is 16013403479. The next prime is 16013403577. The reversal of 16013403533 is 33530431061.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33530431061 = 5741 ⋅5840521.

It is a cyclic number.

It is not a de Polignac number, because 16013403533 - 2⁸ = 16013403277 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16013403496 and 16013403505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16013403233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5562635 + ... + 5565512.

It is an arithmetic number, because the mean of its divisors is an integer number (4006133280).

Almost surely, 2^16013403533 is an apocalyptic number.

It is an amenable number.

16013403533 is a deficient number, since it is larger than the sum of its proper divisors (11129587).

16013403533 is a wasteful number, since it uses less digits than its factorization.

16013403533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11129586.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 16013403533 its reverse (33530431061), we get a palindrome (49543834594).

The spelling of 16013403533 in words is "sixteen billion, thirteen million, four hundred three thousand, five hundred thirty-three".