Base | Representation |
---|---|
bin | 11101110110011011… |
… | …10100101001011001 |
3 | 1112100212111021121220 |
4 | 32323031310221121 |
5 | 230310110133133 |
6 | 11210121522253 |
7 | 1105064413611 |
oct | 167315645131 |
9 | 45325437556 |
10 | 16025864793 |
11 | 6884201464 |
12 | 3133043389 |
13 | 1685240c43 |
14 | ac0585a41 |
15 | 63be045b3 |
hex | 3bb374a59 |
16025864793 has 32 divisors (see below), whose sum is σ = 23028364800. Its totient is φ = 9876362496.
The previous prime is 16025864779. The next prime is 16025864801. The reversal of 16025864793 is 39746852061.
It is not a de Polignac number, because 16025864793 - 213 = 16025856601 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (16025864693) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6025698 + ... + 6028356.
It is an arithmetic number, because the mean of its divisors is an integer number (719636400).
It is a 1-persistent number, because it is pandigital, but 2⋅16025864793 = 32051729586 is not.
Almost surely, 216025864793 is an apocalyptic number.
It is an amenable number.
16025864793 is a deficient number, since it is larger than the sum of its proper divisors (7002500007).
16025864793 is a wasteful number, since it uses less digits than its factorization.
16025864793 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4741.
The product of its (nonzero) digits is 2177280, while the sum is 51.
The spelling of 16025864793 in words is "sixteen billion, twenty-five million, eight hundred sixty-four thousand, seven hundred ninety-three".
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