Base | Representation |
---|---|
bin | 1110100100111101000100… |
… | …0111010100110011011111 |
3 | 2002202021011001200101220212 |
4 | 3221033101013110303133 |
5 | 4100100402010332433 |
6 | 54031102001003035 |
7 | 3242662362331163 |
oct | 351172107246337 |
9 | 62667131611825 |
10 | 16028031339743 |
11 | 511a4a4928955 |
12 | 196a40b32347b |
13 | 8c358aa59a87 |
14 | 3d5a91b08ca3 |
15 | 1cbdd4c82d48 |
hex | e93d11d4cdf |
16028031339743 has 4 divisors (see below), whose sum is σ = 16028153356488. Its totient is φ = 16027909323000.
The previous prime is 16028031339739. The next prime is 16028031339757. The reversal of 16028031339743 is 34793313082061.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16028031339743 - 22 = 16028031339739 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16028031339691 and 16028031339700.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16028031330743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60811121 + ... + 61074122.
It is an arithmetic number, because the mean of its divisors is an integer number (4007038339122).
Almost surely, 216028031339743 is an apocalyptic number.
16028031339743 is a deficient number, since it is larger than the sum of its proper divisors (122016745).
16028031339743 is a wasteful number, since it uses less digits than its factorization.
16028031339743 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122016744.
The product of its (nonzero) digits is 1959552, while the sum is 50.
The spelling of 16028031339743 in words is "sixteen trillion, twenty-eight billion, thirty-one million, three hundred thirty-nine thousand, seven hundred forty-three".
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