16048325113 has 4 divisors (see below), whose sum is σ = 16048755828. Its totient is φ = 16047894400.

The previous prime is 16048325099. The next prime is 16048325171. The reversal of 16048325113 is 31152384061.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31152384061 = 30983 ⋅1005467.

It can be written as a sum of positive squares in 2 ways, for example, as 11736038889 + 4312286224 = 108333^2 + 65668^2 .

It is a cyclic number.

It is not a de Polignac number, because 16048325113 - 2⁵ = 16048325081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16048325413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153556 + ... + 235957.

It is an arithmetic number, because the mean of its divisors is an integer number (4012188957).

Almost surely, 2^16048325113 is an apocalyptic number.

It is an amenable number.

16048325113 is a deficient number, since it is larger than the sum of its proper divisors (430715).

16048325113 is an equidigital number, since it uses as much as digits as its factorization.

16048325113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 430714.

The product of its (nonzero) digits is 17280, while the sum is 34.

The spelling of 16048325113 in words is "sixteen billion, forty-eight million, three hundred twenty-five thousand, one hundred thirteen".