Base | Representation |
---|---|
bin | 1110100110100010010101… |
… | …1000110000111001110011 |
3 | 2002211212022112112111010011 |
4 | 3221220211120300321303 |
5 | 4101022040020014303 |
6 | 54051355225115351 |
7 | 3244644123542410 |
oct | 351504530607163 |
9 | 62755275474104 |
10 | 16055215001203 |
11 | 512aa84345074 |
12 | 1973737028b57 |
13 | 8c60007c3c61 |
14 | 3d71100b9107 |
15 | 1cc9764e616d |
hex | e9a25630e73 |
16055215001203 has 32 divisors (see below), whose sum is σ = 18577360834560. Its totient is φ = 13591054609920.
The previous prime is 16055215001191. The next prime is 16055215001213. The reversal of 16055215001203 is 30210051255061.
16055215001203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 16055215001203 - 221 = 16055212904051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16055215001213) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 370588783 + ... + 370632103.
It is an arithmetic number, because the mean of its divisors is an integer number (580542526080).
Almost surely, 216055215001203 is an apocalyptic number.
16055215001203 is a deficient number, since it is larger than the sum of its proper divisors (2522145833357).
16055215001203 is a wasteful number, since it uses less digits than its factorization.
16055215001203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44947.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 16055215001203 its reverse (30210051255061), we get a palindrome (46265266256264).
The spelling of 16055215001203 in words is "sixteen trillion, fifty-five billion, two hundred fifteen million, one thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •