Base | Representation |
---|---|
bin | 11101111010111111… |
… | …10001011100111101 |
3 | 1112110112111002101201 |
4 | 32331133301130331 |
5 | 230344403442413 |
6 | 11214005535501 |
7 | 1106040543616 |
oct | 167537613475 |
9 | 45415432351 |
10 | 16064124733 |
11 | 68a3863748 |
12 | 3143a14591 |
13 | 1690148767 |
14 | ac56a4c0d |
15 | 6404609dd |
hex | 3bd7f173d |
16064124733 has 4 divisors (see below), whose sum is σ = 16064730400. Its totient is φ = 16063519068.
The previous prime is 16064124709. The next prime is 16064124737. The reversal of 16064124733 is 33742146061.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16064124733 - 229 = 15527253821 is a prime.
It is a super-2 number, since 2×160641247332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16064124692 and 16064124701.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16064124737) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261135 + ... + 316732.
It is an arithmetic number, because the mean of its divisors is an integer number (4016182600).
Almost surely, 216064124733 is an apocalyptic number.
It is an amenable number.
16064124733 is a deficient number, since it is larger than the sum of its proper divisors (605667).
16064124733 is an equidigital number, since it uses as much as digits as its factorization.
16064124733 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605666.
The product of its (nonzero) digits is 72576, while the sum is 37.
The spelling of 16064124733 in words is "sixteen billion, sixty-four million, one hundred twenty-four thousand, seven hundred thirty-three".
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