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16076324755331 = 101159171532231
BaseRepresentation
bin1110100111110000111110…
…1000000101011110000011
32002220212210201021002211122
43221330033220011132003
54101343303114132311
654105210040302455
73246322212516161
oct351741750053603
962825721232748
1016076324755331
115138a27240865
121977848771a2b
138c7cb6086229
143d815391c231
151cd2ae8c30db
hexe9f0fa05783

16076324755331 has 4 divisors (see below), whose sum is σ = 16235496287664. Its totient is φ = 15917153223000.

The previous prime is 16076324755321. The next prime is 16076324755367. The reversal of 16076324755331 is 13355742367061.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16076324755331 - 210 = 16076324754307 is a prime.

It is a super-2 number, since 2×160763247553312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16076324755321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79585766015 + ... + 79585766216.

It is an arithmetic number, because the mean of its divisors is an integer number (4058874071916).

Almost surely, 216076324755331 is an apocalyptic number.

16076324755331 is a deficient number, since it is larger than the sum of its proper divisors (159171532333).

16076324755331 is a wasteful number, since it uses less digits than its factorization.

16076324755331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159171532332.

The product of its (nonzero) digits is 9525600, while the sum is 53.

The spelling of 16076324755331 in words is "sixteen trillion, seventy-six billion, three hundred twenty-four million, seven hundred fifty-five thousand, three hundred thirty-one".

Divisors: 1 101 159171532231 16076324755331