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16100042433 = 329185057959
BaseRepresentation
bin11101111111010001…
…10010011011000001
31112120001001220012220
432333220302123001
5230433102324213
611221331441253
71106655050136
oct167750623301
945501056186
1016100042433
1169120661a2
123153a56229
131697713137
14aca37458d
156436a7e23
hex3bfa326c1

16100042433 has 8 divisors (see below), whose sum is σ = 22206955200. Its totient is φ = 10363245648.

The previous prime is 16100042429. The next prime is 16100042449. The reversal of 16100042433 is 33424000161.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 16100042433 - 22 = 16100042429 is a prime.

It is a super-2 number, since 2×161000424332 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (16100042533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92528893 + ... + 92529066.

It is an arithmetic number, because the mean of its divisors is an integer number (2775869400).

Almost surely, 216100042433 is an apocalyptic number.

It is an amenable number.

16100042433 is a deficient number, since it is larger than the sum of its proper divisors (6106912767).

16100042433 is a wasteful number, since it uses less digits than its factorization.

16100042433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 185057991.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 16100042433 its reverse (33424000161), we get a palindrome (49524042594).

The spelling of 16100042433 in words is "sixteen billion, one hundred million, forty-two thousand, four hundred thirty-three".

Divisors: 1 3 29 87 185057959 555173877 5366680811 16100042433