161003504041 has 4 divisors (see below), whose sum is σ = 161597613184. Its totient is φ = 160409394900.

The previous prime is 161003503987. The next prime is 161003504047. The reversal of 161003504041 is 140405300161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 161003504041 - 2¹⁷ = 161003372969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 161003503997 and 161003504015.

It is not an unprimeable number, because it can be changed into a prime (161003504047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297054165 + ... + 297054706.

It is an arithmetic number, because the mean of its divisors is an integer number (40399403296).

Almost surely, 2^161003504041 is an apocalyptic number.

It is an amenable number.

161003504041 is a deficient number, since it is larger than the sum of its proper divisors (594109143).

161003504041 is an equidigital number, since it uses as much as digits as its factorization.

161003504041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 594109142.

The product of its (nonzero) digits is 1440, while the sum is 25.

The spelling of 161003504041 in words is "one hundred sixty-one billion, three million, five hundred four thousand, forty-one".